Java多线程之ThreadLocal
当前位置:以往代写 > JAVA 教程 >Java多线程之ThreadLocal
2019-06-14

Java多线程之ThreadLocal

Java多线程之ThreadLocal

副标题#e#

ThreadLocal的焦点思想很简朴:为每个独立的线程提供一个变量的副本。

Java提供的synchronized要害字利用了“同步锁”的机制来阻止线程的竞争会见,即“以时间换空间”。: " 10pt; FONT-SIZE:>  ThreadLocal则利用了“拷贝副本”的方法,人人有份,你用你的,我用我的,各人互不影响,是“以空间换时间”。每个线程修改变量时,实际上修改的是变量的副本,不怕影响到其它线程。

为了加深对ThreadLocal的领略,下面我利用一个例子来演示ThreadLocal如何断绝线程间的变量会见和修改:

【1】SerialNum类

package example.thread.threadLocal;

public class SerialNum {

private static int nextSerialNum = 1;

@SuppressWarnings("unchecked")
private static ThreadLocal serialNum = new ThreadLocal() {
protected synchronized Object initialValue() {
return new Integer(nextSerialNum++);
}
};

public static int get() {
return ((Integer) (serialNum.get())).intValue();
}

@SuppressWarnings("unchecked")
public static void set(Integer newSerial){
serialNum.set(newSerial);
}
}

【2】GetSerialNumThread

package example.thread.threadLocal;

public class GetSerialNumThread implements Runnable {

public static void main(String args[]) {

GetSerialNumThread serialNumGetter = new GetSerialNumThread();
Thread t1 = new Thread(serialNumGetter, "Thread A");
Thread t2 = new Thread(serialNumGetter, "Thread B");
t1.start();
try {
t1.join();
} catch (InterruptedException e) {
e.printStackTrace();
}
t2.start();
}

public void run() {
int mySerialNum = getSerialNum();
System.out.println("线程 " + Thread.currentThread().getName()
+ " 获取到的序列号是" + mySerialNum);
System.out.println("线程 " + Thread.currentThread().getName()
+ " 修改了序列号为" + (mySerialNum * 3));
setSerialNum(mySerialNum * 3);
System.out.println("线程 " + Thread.currentThread().getName()
+ " 再次得到的序列号是" + getSerialNum());
}

private int getSerialNum() {
return SerialNum.get();
}

private void setSerialNum(int newSerialNum) {
SerialNum.set(new Integer(newSerialNum));
}
}

运行的功效如下:

线程 Thread A 获取到的序列号是1

线程 Thread A 修改了序列号为3

线程 Thread A 再次得到的序列号是3

线程 Thread B 获取到的序列号是2

线程 Thread B 修改了序列号为6

线程 Thread B 再次得到的序列号是6


#p#副标题#e#

可见第一个线程在挪用SerialNum.set(int)要领修改static变量时,其实修改的是它本身的副本,而不是修改当地变量,第二个线程在初始化的时候拿到的序列号是2而不是7。

为什么会这样呢?显着serialNum是静态变量啊?其实我们只需要看看ThreadLocal的内部结构就知道了:

A. ThreadLocal的get()要领:

/**
* Returns the value in the current thread's copy of this thread-local
* variable. Creates and initializes the copy if this is the first time
* the thread has called this method.
*
* @return the current thread's value of this thread-local
*/
public T get() {
Thread t = Thread.currentThread();
ThreadLocalMap map = getMap(t);
if (map != null)
return (T)map.get(this);

// Maps are constructed lazily. if the map for this thread
// doesn't exist, create it, with this ThreadLocal and its
// initial value as its only entry.
T value = initialValue();
createMap(t, value);
return value;
}

B. ThreadLocal的set()要领:

/**
* Sets the current thread's copy of this thread-local variable
* to the specified value. Many applications will have no need for
* this functionality, relying solely on the {@link #initialValue}
* method to set the values of thread-locals.
*
* @param value the value to be stored in the current threads' copy of
* this thread-local.
*/
public void set(T value) {
Thread t = Thread.currentThread();
ThreadLocalMap map = getMap(t);
if (map != null)
map.set(this, value);
else
createMap(t, value);
}

#p#分页标题#e#

可以看到ThreadLocal在内部维护了一个Map,将变量的值和线程绑定起来,get/set要领都是对该线程对应的value举办操纵,所以不会影响到其它线程。

    关键字:

在线提交作业