用几十行代码实现python中英文分词
说到分词各人必定一般认为是很高妙的技能,可是本日作者用短短几十行代码就搞定了,叹息python很强大啊!作者也很强大。不外这个只是正向最大匹配,没有呆板进修本领
留意:利用前先要下载搜狗词库
# -*- coding:utf-8 -*- #写了一个简朴的支持中文的正向最大匹配的机器分词,其它不消表明白,就几十行代码 #附:搜狗词库下载地点:http://vdisk.weibo.com/s/7RlE5 import string __dict = {} def load_dict(dict_file='words.dic'): #加载词库,把词库加载成一个key为首字符,value为相关词的列表的字典 words = [unicode(line, 'utf-8').split() for line in open(dict_file)] for word_len, word in words: first_char = word[0] __dict.setdefault(first_char, []) __dict[first_char].append(word) #按词的长度倒序分列 for first_char, words in __dict.items(): __dict[first_char] = sorted(words, key=lambda x:len(x), reverse=True) def __match_ascii(i, input): #返回持续的英文字母,数字,标记 result = '' for i in range(i, len(input)): if not input[i] in string.ascii_letters: break result += input[i] return result def __match_word(first_char, i , input): #按照当前位置举办分词,ascii的直接读取持续字符,中文的读取词库 if not __dict.has_key(first_char): if first_char in string.ascii_letters: return __match_ascii(i, input) return first_char words = __dict[first_char] for word in words: if input[i:i+len(word)] == word: return word return first_char def tokenize(input): #对input举办分词,input必需是uncode编码 if not input: return [] tokens = [] i = 0 while i < len(input): first_char = input[i] matched_word = __match_word(first_char, i, input) tokens.append(matched_word) i += len(matched_word) return tokens if __name__ == '__main__': def get_test_text(): import urllib2 url = "http://news.baidu.com/n?cmd=4&class=rolling&pn=1&from=tab&sub=0" text = urllib2.urlopen(url).read() return unicode(text, 'gbk') def load_dict_test(): load_dict() for first_char, words in __dict.items(): print '%s:%s' % (first_char, ' '.join(words)) def tokenize_test(text): load_dict() tokens = tokenize(text) for token in tokens: print token tokenize_test(unicode(u'瑰丽的花圃里有各类百般的小动物')) tokenize_test(get_test_text())
我也进修啦~~~